Using a virtual fly experiment We complete the cross describ

Using a virtual fly experiment We complete the cross described in #3, and the results are provided below: Are these results consistent with the expected outcomes you proposed in #3 above? Use a chi-square analysis to provide support for your answer and Clearly state the expected F2 phenotypic ratio based on question 3 above. This is your hypothesis under the current experimental design. What are the expected numbers of individuals for each of the four observed F2 phenotypes based on your hypothesis? What is your calculated chi-square test statistic? What are the degrees of freedom and the chi-square critical value for this analysis? Do you reject or fail to reject hypothesis based on this analysis?

Solution

Null Hypothesis : The observed values are not deviating form 9:3:3:1 ratio.

Categories

Wild Wild

Wild sepia

Curved Wild

Curved Sepia

Total

Observed Values

674

215

224

80

1193

Expected values

9

3

3

1

16

Exprected ratio

671.0625

223.6875

223.6875

74.5625

Deviation

2.9375

-8.6875

0.3125

5.4375

D^2

8.62890625

75.472656

0.09765625

29.56640625

D^2/E

0.012858573

0.3374022

0.000436574

0.396531852

0.747229

X^2

0.747229207

Degrees of Freedom

No of categories - 1

4-1

3

Inference: The caculated chisquare value is less than the table value i.e. 7.82 at 0.05 probablity and 3 DF. Hense Null hypothesis accepted.

The exprected individuals are
671.0625   223.6875   223.6875   74.5625

What is your calculted chisquare test statistic
0.747229207

Degrees of freedom
No of categories - 1:   4-1:   3

Categories	Wild Wild	Wild sepia	Curved Wild	Curved Sepia	Total
Observed Values	674	215	224	80	1193
Expected values	9	3	3	1	16
Exprected ratio	671.0625	223.6875	223.6875	74.5625
Deviation	2.9375	-8.6875	0.3125	5.4375
D^2	8.62890625	75.472656	0.09765625	29.56640625
D^2/E	0.012858573	0.3374022	0.000436574	0.396531852	0.747229
X^2	0.747229207
Degrees of Freedom	No of categories - 1	4-1	3