Show that the subset S 0 4 8 12 16 20 of Z24 is a subring D
Show that the subset S = {[0], [4], [8], [12], [16], [20]} of Z24 is a subring. Does S have an identity?
Solution
Note that we can characterize the set S as S = {[4q]24 : q Z}. By inspection we see that [0]24 S. Also, for any a, b S we have a = [4q]24 and b = [4r]24 for some integers q, r Z. So a + b = [4q] + [4r] = [4(q + r)] S, ab = [4q][4r] = [4(4qr)] S, and a = [4q] = [4(q)] S. By Theorem 3.2, S is a subring of Z24
Hence Proved.
Yes S have an identity.
![Show that the subset S = {[0], [4], [8], [12], [16], [20]} of Z24 is a subring. Does S have an identity?SolutionNote that we can characterize the set S as S = { Show that the subset S = {[0], [4], [8], [12], [16], [20]} of Z24 is a subring. Does S have an identity?SolutionNote that we can characterize the set S as S = {](/WebImages/5/show-that-the-subset-s-0-4-8-12-16-20-of-z24-is-a-subring-d-985064-1761505993-0.webp)
