Two fair sixsided dice are rolled What is the probability th

Two fair six-sided dice are rolled. What is the probability that one die shows exactly one more than the other die (for example, rolling a 1 and 2, or rolling a 5 and a 4).

Solution

When two dice are rolled there are total 36 cases. Out of these 36 ordered pairs, the pairs ( 1,2) ,(2,1),(2,3),(3,2),(3,4),(4,3),(4,5),(5,4),(5,6) and (6,5) are total 10 cases in which one die shows exactly one more than the other die.

Now as Probablity P( Any event ) = Total favorable cases/ Total cases

So P( One die has one more than other die) = 10/36

=5/18

that is last answer.