A rigid insulated vessel is divided into two equalvolume com
Solution
Mass of water = density * 1 m^3
density from steam tables @20 C x = 0.5 = 0.0346 kg/m^3
Pressure = 2.34 kPa
initial entropy = 4480 J/kg K
mass of water = 0.0346 kg
final density of water after valve is opened = 0.0346 / 2 = 0.0173 kg/m^3
Final Pressure = 2.34 kPa
from steam tables at 2.34 kPa and density = 0.0173 kg/m^3
we get superheated vapor at 20.3 C (final temperature)
final entropy s2 = 8670 J/kg K
Change in entropy = m * (s2 - s1)
= 0.0346 * (8670 - 4480 ) = 144.974 J/K

