C Language Problem Please Explain If int n1 5 and int d1 2

C Language Problem

Please Explain

If int n1 = 5, and int d1 = 2, what are the results of the following operations? (assume double frac) frac = (double)n1/(double)d1;frac = (double)n1/d1 + 3.5; frac = (double)(n1/d1) + 2.5;

Solution

Here the heart of functionality is typecasting.

What is typecasting?

Type casting is a way to convert a variable from one data type to another data type.

frac = (double)n1/(double)d1;

n1 = 5 and d1 = 2

what this  (double)n1/(double)d1 does..

here typecasting is preforming so

(double)n1 = 5.000000

(double)d1 = 2.000000

frac =  5.000000/2.000000

frac = 2.500000

frac = (double)n1/d1 + 3.5;

Here only n1 is typecasted into double

so n1 is 5.000000

and d1 is 2

(double)n1/d1 + 3.5 => (5.000000 / 2) + 3.5 => 2.500000 + 3.5 => 6.000000

frac is 6.000000

frac = (double)(n1/d1) + 3.5;

here there is no typecasting between n1 and d1 ... after division is perform then typecasting is going to applied

so

(double)(n1/d1) + 3.5

(double)(5/2) + 3.5

(double)(2) + 3.5

2.000000 + 3.5

5.500000

Answer is 5.500000