Use the given information to find the Pvalue normal distribu

Use the given information to find the P-value (normal distribution was used) The test statistic is a two-tailed test is z= 3.72

Solution

Using a table/technology, the left tailed area of this is          
          
P(z <   3.72   ) =    0.999900389
          
Thus, the right tailed area is the complement,          
P(z >   3.72   ) =    9.96114E-05

hence, the two tailed area is twice this,

P = 2*9.96114E-05 = 0.000199223 [ANSWER]