3 If the albino phenotype occurs in 110000 individuals in a

3. If the albino phenotype occurs in 1/10,000 individuals in a population at equilibrium, and albinism is caused by an autosomal recessive allele a, calculate the frequency of: A. The recessive mutant allele (2 points) B. The normal dominant allele (2 points) C. Heterozygotes in the population (2 points) D. Mating between heterozygotes (2 points)

Solution

A. Frequency of recessive mutatnt genotype = 1/ 10,000 = 0.0001

The frequencu of recessive mutant allele = 0.01

B. Frequency of normal dominant allele = 1 - 0.01 = 0.99

C. Frquency of heterozygotes in population = 2pq = 2 (0.99) (0.01) = 0.0198

Numer of heterozygotes = 0.0198 x 10,000 = 198

D. Mating between heterozygotes

Aa X Aa

AA1:Aa 2 : aa1

The resultant frequencies of genotype AA, Aa and aa are = 0.99, 0.0198 and 0.01