Solve the following triangle ABC All sides are measured in f

Solve the following triangle ABC. All sides are measured in feet. a = 8, b = 14, c = 19 A = degree, B = degree, C = degree.

a = 8

b = 14

c = 19

Now a = sqrt[b^2 + c^2 - 2bc*cosA]

8 = sqrt[14^2 + 19^2 - 2*14*19*cosA] = sqrt[557 - 532*cosA]

cosA = 0.92669 ==========> A = 22.1 degree

And

b = sqrt[a^2 + c^2 - 2ac*cosB]

14 = sqrt[8^2 + 19^2 - 2*8*19*cosB] = sqrt[425 - 304*cosB]

cosB = 0.753289 ==========> B = 41.1 degree

Then C = 180 - A - B = 180 - 22.1 - 41.1 = 116.8 degree