The test statistic in a left tailed test is z 245 Determin

The test statistic in a left tailed test is z = - 2.45. Determine the P-value and decide whether, at the 1% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. 0 Click here to view a partial table of areas under the standard normal curve.

Solution

for this question we need to use the tables of Z standard variable that is for a normal distribution

we will find P value of Z = -2.45 in the tables of Z standard variable

you just need to find a value of Z = 2.45 ( is the same for negative) and see the value of probability for that Z

P value is 0.00714

round to four decimals P value = 0.0071

significance level = 0.01 ( left tailed is one tail test)

decision rule:

IF P VALUE IS GREATER THAN SIGNIFICANCE LEVEL WE FAIL TO REJECT HO (ACCEPT)

IF P VALUE IS LESS THAN SIGNIFICANCE LEVEL WE REJECT HO

CONCLUSION:

since P value is less than 0.01 we reject Ho

the data provide sufficient evidence to reject Ho