A piece of copper having a mass of 185 kg is placed in a boi

A piece of copper having a mass of 1.85 kg is placed in a boiling water bath until it reaches thermal equilibrium. It is then placed into a beaker containing 0.70 kg of water at 20 degree C. What is the final equilibrium temperature of the water-copper combination?

Solution

mass of copper m = 1.85 kg

Initial temprature t = 100 o C

Mass of water M = 0.7 kg

Initial temprature of water t \' = 20 o C

Specific heat of copper C = 384.4 J / kg oC

Specific heat of water C \' = 4186 J / kg o C

Heat lost by copper = heat gain by water

   mC(100 -T ) = MC\'(T - 20 )

1.85 (384.4)(100-T) = 0.7(4186)(T-20)

71114 -711.14 T = 2930.2 T - 58604

         3641.34 T = 129718

                     T = 35.62 o C

 A piece of copper having a mass of 1.85 kg is placed in a boiling water bath until it reaches thermal equilibrium. It is then placed into a beaker containing 0

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site