An airplane climbs at an angle of 11 degrees with the ground

An airplane climbs at an angle of 11 degrees with the ground. Find the ground distance it has traveled when it has attained an altitude of 400 feet .   

Solution

Given angle = 11 degrees

Height (altitude) = 400 feet.

Then tan(theata) = height / base

Base length = 400/ tan(11)

                   = 400/0.1944

                  = 2057. 6 ft