The area of a rectangle is 48 square centimeters if the leng
The area of a rectangle is 48 square centimeters. if the length and width are each increased by 4 centimeters, the area of the newly formed rectangle is 120 square centimeter. Find the dimensions of the original retangle.
Solution
Let the length of the rectangle = x
and width of the rectangle = y
Then we have xy = 48.......................(1)
Now when we changed the dimension
new length = x+4
and new width = y+4
Hence new area
A= (x+4) (y+4) = 120
=> xy + 4x+4y +16 = 120
=> 48 + 4x + 4(48/x) +16 = 120
=> 4x+ 192/x +64 = 120
=> x+ 48/x +16 = 30
=> x^2 +48 +16x = 30x
=> x^2 - 14x +48 =0
=> x^2 -8x-6x +48 =0
=> (x-8) (x-6) = 0
=> x= 8, 6
when x= 8 , y= 48/8 = 6
when x= 6 , y= 48/6 = 8
