A plane leaves an airport at 3pm At 4pm another plane leaves
A plane leaves an airport at 3pm. At 4pm another plane leaves the same airport traveling in the same direction at a speed 150 mph faster than that of the first plane. Four hours after the first plane takes off, the second plane is 250 miles ahead of the first plane. How far does the second plane travel?
Solution
x*4=d
(x+150)*3=d+250
d = 800, x = 200
d+250=800+250=1050 second plane
350*3=1050 miles second plane
4*200=800 first plane
