Homework Sourse03483 00096 03557 00146 A 03483 B 00096 C 03557 D 00146 Solu
0.3483
0.0096
0.3557
0.0146
| A. | 0.3483 | |
| B. | 0.0096 | |
| C. | 0.3557 | |
| D. | 0.0146 |
Solution
Mean ( u ) =114.8
Standard Deviation ( sd )=13.1
Number ( n ) = 36
Normal Distribution = Z= X- u / (sd/Sqrt(n) ~ N(0,1)
P(X < 110) = (110-114.8)/13.1/ Sqrt ( 36 )
= -4.8/2.1833= -2.1985
= P ( Z <-2.1985) From Standard NOrmal Table
= 0.0146
