A highway engineer knows that his crew can lay 5 miles of hi
A highway engineer knows that his crew can lay 5 miles of highway on a clear day, 2 miles on a rainy day, and only 1 mile on a snowy day. Suppose the probabilities are as follows: A clear day: .6, a rainy day: .3, a snowy day: .1. What are the mean and variance?
Solution
Consider the table:
x P(x) x P(x) x^2 P(x)
5 0.6 3 15
2 0.3 0.6 1.2
1 0.1 0.1 0.1
Totals 3.7 16.3
=E(x) =E(x^2)
Thus,
E(x) = 3.7 [MEAN]
Var(x) = E(x^2) - E(x)^2 = 2.61 [VARIANCE]
