Please complete the table and show calculations 12 V 200 100

Please complete the table and show calculations

12 V 20.0 10.0 (2 10.0 2.0 Battery 20 10 10 2 20 10 2

R1=20 ohm

R2=10 hm

R3=10 ohm

R4=2 Ohm

since R 1 2 3 are in parallel so eqv 1/R123 = 1/20+1/10+1/10. so R123 = 4 ohm

now R123 and R4 are in series so R1234= 6 ohm

So total current through circuit= V/R1234 = 12/6=2 A

So current through R4 , will be all the current , I4=2 A

Voltage through R4 , V4 = I4*R4=4 V

Now current 2 A is divided across R1 R2 R3 in inverse prportion to resistor and volateg across them would be 12-4 = 8V.

So I1= 8/R1= 8/20= .4 A.

I2=8/R2=.8A

I3=8/R3=.8A

V1=V2=V3=8A