A find the magnitude at the field of origin B find the magni

Solution

a) E1= electric field at origin due to q

= k*q/(0.325)^2 -y^

= 9*10^9*4.2*10^-6/(0.325)^2

=357.87*10^3 N/C -y^

E2= electric field at origin due to q\'

= k*q\'/(0.394)^2 x^

=266.69*10^3. x^

E= net electric filed at origin

= E1+E2

= 10^3*(-357.87 y^ +266.69 x^)

|E|= magnitude of E=(E1^2+E2^2)^0.5=446.3*10^3 N/c

(b) r= distance between q and q\'

=(0.325^2+0.394^2)^0.5

=0.509

F1 = force on q due to q\'

=k q*q\'/r^2

=74.57*10^-3 N

C) theta = tan^-1(0.325/0.394)= 39 degree.

Direction= 39 degree from negative x axis or (180-39) degree from positive x axis