The parallel Plate Capacitor epsilon0 14 pi K 885 times 10

The parallel Plate Capacitor epsilon_0 = 1/4 pi K = 8.85 times 10^-12 c^2/(N middot m^2) = 8.85 times 10^-12 F/m A_disc = pi r^2 K_air = 1.00059 = 1.00 C_p = Ke0A/d

Solution

A2)

1 nF =1*10^-9F

Given

C_exp=0.071 nF

C_exp=0.071*1*10^-9 =7.1*10^-11F

A3)

Area of the disc

A=pi*R² =pi*0.1² =0.0314 m²

Seperation between the discs is

d=0.004 m

Capacitance

C=Ke_oA/d =1*(8.85*10^-12)*0.0314/0.004

C=6.9508*10^-11 F