y1 10x 3 y2 4x 7 and y1 exceeds y2 by 2SolutionGiven y1

y_1 = 10x - 3, y_2 = 4x + 7, and y_1 exceeds y_2 by 2.

Given

y₁ = 10x -3

y₂ = 4x + 7

y₁ exceeds y₂ by 2

i.e. y₁ = y₂ + 2

now we subtituite values for y₁ and y₂ in the above equation

10x - 3 = (4x + 7) + 2

10x - 3 = 4x +7 +2

10x - 3 = 4x + 9

we subtract \"4x\" from both the sides

10x -3 -4x = 4x + 9 -4x

6x - 3 = 9

now we add \"3\" both the sides

6x -3 +3 = 9 +3

6x = 12

we divide both sides by \"6\"

6x/6 = 12/6

x = 2