What is the output of the following code value of a and valu

What is the output of the following code (value of a and value of b)? voidfuncl(lnt*p1, int.p2) {int temp; temp = * p1; *p1 = *p2; *p2 = temp;} int main() {int a = 10, b = 20; func1(&a;, &b;); cout

Solution

The output of above code is as follows

value of a is 20

value of b is 10

Explanation:

Initially value of a =10        and b=20

The funct1() is called by address, Address of a and address of b are passed to funct1()

In the called function the formal arguments are pointer p1 and p2.

P1 points to the address of a , and p2 points to the address of b.

Here a swap operation is performed that exchange the values of a and b throuhthier address. So as arguments are passed by address, changes in the formal argument also reflects in the actual arguments.

SO a is now 20 and bis now 10.