Find f by solving the initial value problem f x6x26x f27Solu

Find f by solving the initial value problem.

f \'(x)=6x^2-6x

f(2)=7

f \'(x)=6x^2-6x

f(x) = 6x^3/3 - 6x^2/2 + c

f(x) = 2x^3 - 3x^2 + c

f(2)=7

f(2) = 7 = 2 * 8 - 3*4 + c

c=3

So,

f(x) = 2x^3 - 3x^2 + 3

$Find f by solving the initial value problem. f \'(x)=6x^2-6x f(2)=7Solutionf \'(x)=6x^2-6x f(x) = 6x^3/3 - 6x^2/2 + c f(x) = 2x^3 - 3x^2 + c f(2)=7 f(2) = 7 = 2$

Find f by solving the initial value problem f x6x26x f27Solu

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