Number Theory and its application Need a detailed explanatio
Number Theory and its application
Need a detailed explanation. thx.
Solution
3
Part a)
Sum of a million different number, each roughly equal to one million:
Since each number is roughly equal to one million, therefore for estimation purpose, we can consider that each of the number is exactly equal to one million. One million being added to itself one million times can be found by multipying one million to itself.
Therefore, number of bits = 2*(number of bits in one million)-1
We know that there are 7 bits in one million, therefore, the required bit length is = 2*7-1 = 14-1 = 13
Therefore, bitlength would be 13 for part (a).
Part b)
Product a million different numbers, each roughly equal to one million:
This quantity can be written as one million raised to one million. That is, 10000001000000
We know that number if bits in n^n is equal to (n+1). Therefore, number of bits in 10000001000000 are (1000000+1) = 1000001
Therefore, bitlengh for part b is 1000001.
