1 pt For each of the given the data sets below calculate the

(1 pt) For each of the given the data sets below, calculate the mean and standard deviation.

Solution

Mean = (3.6+3.9+2.1+4.7+2.3+4.8)/6=21.4/6=3.5667

Difference from mean of each 3.6-3.5667, 3.9-3.5667, 2.1-3.5667, 4.7-3.5667, 2.3-3.5667, 4.8-3.5667

That is: 0.033, 0.333, -1.4667, 1.133, -1.267, 1.233

Their squares are: 0.0011, 0.1111, 2.1511, 1.2844, 1.6044,1.5211

Sum of squares =  0.0011+0.1111+ 2.1511+1.2844+1.6044+1.5211=6.6732

Average sum of squares = 6.6732/6=1.1122

Standard deviation = Square root of average sum of squares = 1.0546

(1 pt) For each of the given the data sets below, calculate the mean and standard deviation.SolutionMean = (3.6+3.9+2.1+4.7+2.3+4.8)/6=21.4/6=3.5667 Difference

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site