Two cyclists 90 mi apart start riding toward each other at t

Two cyclists, 90 mi apart, start riding toward each other at the same time. One cycles twice as fast as the other. If they meet 2h later, at what average speed is each cyclist traveling?

Solution

D=RT
90=(X+2X)2
90=3X*2
90=6X
X=90/6
X=15 MPH FOR THE SLOWER CYCLIST.
2*15=30 MPH FOR THE FASTER CYCLIST.
PROOF;
90=(15+30)2
90=45*2
90=90