Inside a vacuum chamber a point charge q1 is separated by a

Inside a vacuum chamber, a point charge q1 is separated by a distance d from the surface of a hollow sphere with a radius r and made of a conducting material. The sphere has a charge q2. Notes k is the coulomb\'s law constant. What is the electric field strength a distance r/2 from the center of the sphere? The curve shown is made from a nonconducting material. It holds a positive charge on its top half and a negative charge on its bottom half. Which of the following represents the direction of the net electric field at point a? A and B below are neutral conductors hanging from a string that do not conduct electricity. If a positively charged rod is placed near A as shown, and B is then separated from A: Both A and B will be positively charged Both A and B will be negatively charged A will be positively charged and B will be negatively charged B will be positively charged and A will be negatively charged

Solution

1)

As the charge stored inside the hollow sphere is 0.

So, by Gauss Law, the Electric field inside the sphere must be 0

2)

Answer will be a) South

This is due to the fact that the Electric field due to the charge on the top half will be towards South- East

And for the charge on the bottom half will be towards South West.

So, the net electri field will be towards South

3)

Due to induction, the charge on sphere A will be -ve and on B will be +ve (for maintaining charge neutrality)

So, answer is d)