You want to determine the linear order and genetic distance
Solution
Female parent genotype - g + m/ + o +
Here, g + m and + o + are parental class, so, non cross over = 540+560=1100
Frequency of D.C.O= {(46+37)/2000}*100= 4.15%
Frequency of first S.C.O = {(162+170)/2000}*100=16.60%
Frequency of other S.C.O = {(245+240)/2000}*100 = 24.25%
b) Comparing parental type with D.C.O type, we found that o is uncommon, so o is placed in the middle. So, gene order - g------o---------- m
c) So, map distance between g and o- (16.60+4.15) = 20.75cM and
map distance between o and m - (24.25+4.15) = 28.40 cM.
d) Expected D.C.O - {(20.75/100)*(28.40/100)} = 0.0589
Observed D.C.O - (4.15/100) = 0.0415
C.O.C = Observed D.C.O/Expected D.C.O = 0.0415/0.0589 = 0.704
Interference = 1-0.704 = 0.296
As the interference value is between 0 and 1 thus it indicates partial interference.
