Homework SourseFind 6cos4x in terms of cos xSolution6cos22x formulacos2A2co
Find 6cos(4x) in terms of cos x.
Solution
6cos(2*2x)
formula:cos2A=2cos2A -1
=6[2cos2(2x) -1]
=6[2(cos(2x))2 -1]
=6[2(2cos2(x) -1)2 -1]
=6[2(4cos4(x) -4cos2(x) +1) -1]
=6[8cos4(x) -8cos2(x) +2 -1]
=6[8cos4(x) -8cos2(x) +1]
![Find 6cos(4x) in terms of cos x.Solution6cos(2*2x) formula:cos2A=2cos2A -1 =6[2cos2(2x) -1] =6[2(cos(2x))2 -1] =6[2(2cos2(x) -1)2 -1] =6[2(4cos4(x) -4cos2(x) +1](/WebImages/6/find-6cos4x-in-terms-of-cos-xsolution6cos22x-formulacos2a2co-987704-1761507573-0.webp "Find 6cos(4x) in terms of cos x.Solution6cos(2*2x) formula:cos2A=2cos2A -1 =6[2cos2(2x) -1] =6[2(cos(2x))2 -1] =6[2(2cos2(x) -1)2 -1] =6[2(4cos4(x) -4cos2(x) +1")
