Given the tables of probabilities for the random variable x
Given the tables of probabilities for the random variable x, do these form a probability distribution? Give a reason for your answer
x
0
1
2
3
4
P (x)
0.02
0.07
0.22
0.27
0.42
x
5
10
15
20
P (x)
0.10
- 0.30
0.50
0.70
| x | 0 | 1 | 2 | 3 | 4 |
| P (x) | 0.02 | 0.07 | 0.22 | 0.27 | 0.42 |
Solution
Solution:
Since sum of probabilities =1
x 0 1 2 3 4
P(X):0.02+0.07+0.22+0.27+0.42=1
these form a probability distribution
Since the sum of probabilities=1
that is
X: 5 10 15 20
P(x)0.10+(-0.30)+0.50+0.70=1
these form a probability distribution

