Factor completely write without negative exponents 8x253 x1
Factor completely ; write without negative exponents
8(x^2+5)^-3 (x-1)^3 - 3(2x)(x-1)^4(x^2+5)^-4
show steps please
Solution
8(x2+5)-3 (x-1)3 - 3(2x)(x-1)4(x2+5)-4
formula :a-m=1/am
(8((x-1)3/(x2+5)3))- (3(2x)(x-1)4/(x2+5)4)
=[(8((x-1)3(x2+5)) - (3(2x)(x-1)4)]/(x2+5)4
=[(8(x2+5) - (3(2x)(x-1))] [(x-1)3/(x2+5)4]
=[(8x2+40) - (6x2-6x)] [(x-1)3/(x2+5)4]
=[2x2+6x+40)] [(x-1)3/(x2+5)4]
=2[x2+3x+20)] [(x-1)3/(x2+5)4]

