HELP I need help wth this networking question Thanks Given t

HELP!!! I need help wth this networking question!! Thanks

Given the following starting network and mask 185.64.0.0/10. Subnet to provide 115 subnets. For subnet # 110,

calculate the Subnet ID and mask (enter your answer as a.b.c.d/mask).:

What is the IP address of the first usable host on this subnet?:

What is the IP address of the last usable host on this subnet?:

What is the broadcast address for this subnet?:

Solution

Dear student,

Subnetting is a process of breaking large network in small networks known as subnets.

Given IP address is the class B address. The default subnet mask of class B address is 255.255.0.0.

So given Ip is 185.64.0.0/10

Because mask is 10 so binary representation of the IP address is--

11111111.11000000.00000000.00000000

The subnet ID and mask of the above IP would be..255.192.0.0/10.

Calculation for total subnet...

To calculate the number of subnets provided by given subnet mask we use 2^N , where N = number of bits borrowed from host bits to create subnets. So in our case 185.64.0.0/10, N is 2. By looking at address we can determined that this address is belong to class B and class B has default subnet mask 255.255.0.0/16 . In given address we borrowed 10-8 = 2 host bits to create subnets. Now 2² = 4.So there will be four subnet.

Calculation of Block size of each subnet

And the size of each subnet would be...256-192=64.

So There are four subnet....0,64,128,192.

How to calcuate the Toatl number of host..

For the given number total number of host will be...2^N

So here Value of N = 32-16 = 16

Total number of host= 2¹⁶=65536 host per subnet.

We have to reduce host by 2 so the valid host per subnet will be 65536-2=65534, beacuse one bit reserved for network id and one for broadcast id.

So given IP provide 4 subnets.

Answer No-1

For subnet 110 the subnet ID wold be...185.128.110.0/10.

Answer No-2

IP address of the first usable subnet will be-185.64.1.0/10.

Answer No-3

IP address of the Last usable host will be...185.128.115.0/10.

Answer No-4

Broadcast address of the Last host will be..185.128.191.255

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Answer Number