Would it be possible for someone to help me with this proble

Would it be possible for someone to help me with this problem, not just the answer but a full breakdown of how one would get the answer, and the concept components behind it? Thank you

Solution

D = 6.0 cm = 0.060 m, so, R = radius = 0.030 m. H = 10.0 cm = 0.100 m. V = Pi*R^2*H So, V = 3.1416*0.030*0.030*0.100 m3 = 0.00028274 m3 = 282.74 cm3 Error will be: dV = (Pi*H)*2RdR + (Pi*R^2)*dH So, dV/V = 2(dR/R) + (dH/H) So, error% = 2*(0.1 cm/3 cm)*100 + (0.1 cm/10 cm)*100 = 7.67% So, error in volume calculation/measurement = 0.0766*282.7 cm3 = 21.67 cm3.