Using standard molecular techniques you isolate the gene tha

Using standard molecular techniques, you isolate the gene that seems to be responsible for susceptibility to the drug. The sequence of the dominant and recessive alleles is shown below. The sequence of the propositus is also shown (two alleles, as the individual is human and thus diploid). Based on this data, will the propositus be able to be cured with the drug? Why or why not? Dominant allele: 5\'-AATAGACAGTACAGTAGGGACCGAGAGTTTAGTAG-3\' Recessive allele: 5\'- AATAGACAGTACAGTAGGGACTGAGAGTTTAGTAG-3\' Propositus allele 1: 5\'- AATAGACAGTACAGTAGGGACTGAGAGTTTAGTAG-3\' Propositus allele 2: 5\'- AATAGACAGTACAGTAGGGACTGAGAGTTTAGTAG-3\' Based on the data given in Q2, you choose to confirm with a restriction digest using an enzyme that cuts the recessive allele on the 5\' side of the polymorphism. This the enzyme does NOT cuts the dominant allele. Based on this information, draw the bands in the gel below. Also write the size of each band. Use the ladder given to determine how far the fragments will travel on the gel.

Solution

The given sequence has 35 bp and of this the 22nd bp is replaced by T in place of C in recessive allele, the codon reads asTGA in recessive and CGA in dominant allele. The propositus has recessive allele. here assuming that the recessive character gives susceptability to the drug, i can say that the propositus can be cured with the drug since both alleles are recessive.

During translation the dominant codon codes for (CGA) alanine where as the recessive one codes (TGA) for Threonine. maybe this change is what makes it susceptible to the drug.

Part two of the question regarding the bands.

Since the propositus alleles are recessive the enzyme treated will cut at the recessive 5’ site splitting it in to two fragments, one 21bp long and other 14 bp long. Since both the alleles are same even the father and grandfathers alleles should also yield the same result.

So in the gel we will be able to see two bands in the Cut II treated track, one band a little above 20bp mark and another just below 15bp mark. And in the no enzyme treated track only one band at 35bp mark will be visible.

The father and peternal grand father will also show similar banding pattern as it is a homologus recessive allele.