A box is being pulled across a rough surface with nonzero co
     A box is being pulled across a rough surface (with non-zero coefficient of kinetic friction) at a constant velocity by a force F_p that Ls oriented at an angle of theta to the horizontal, as depicted in the figure. What is the magnitude of the force F_p?  mu_k mg/(cos theta+ mu_k sin theta)  mu_k mg/(cos theta - mu_k sin theta)  mu_k mg/sin theta  mu_k mg (mu_k cos theta - sin theta)  mu_k mg/cos theta 
  
  Solution
Fpcos(thetha) = Friction = uk*(mg-Fpsin(thetha))
=> Fp = ukmg/(cos(thetha)+uk*sin(thetha)
option A

