What would be the answer for a combination probability of 4

What would be the answer for a combination probability of (4 over 0)? Note: There\'s no line between 4 and 0, they are directly on top of each other

Solution

Combination.

It can also be written

C(n, k)

(where n and k are numbers)

It is the number of ways that you can pick k objects, out of a collection of n objects.

C(n, k) = n! / k!(n-k)!

where ! means \"factorial\"

as in 5! = 1*2*3*4*5 = 120

C(5, 2) = 5!/ 2!3! = 120/(2*6) = 10

This would be written as a set of big parentheses, with a 5 on top of the 2, no bar between them).

There are ten ways to pick two objects out of a collection of five:

five objects: ABCDE

10 possible doublets: AB AC AD AE BC BD BE CD CE DE

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Very convenient to calculate the odds in a lottery.

A lottery picks 6 numbers out of 49. The number of possible combinations are:

C(49, 6) = 49! / 6!43! = 13,983,816