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https//www.mathul.com/Student/playerTest ispintestid 919301 08dentenein yes&frompiaymcheck; yes Heather Rhea 3/5 Use the given confidence level and sample data to (a) the margin of error and (b) confidence interval for the population mean find the u As that the population has a normal distribution sume Weight lost on a diet 99% confidence; n 61.x 30 kg s 48 kg View instr Click the icon to view a table of critical t values C. (U) (a E- kg Round to one decimal place as needed) What is the confidence interval for the population mean p? kg

Solution

a)

margin of error = z-score * standard deviation/sqrt(size of sample)

=z * s/sqrt(n)

= 2.575 * 4.8/sqrt(61)

= 1.6 kg

b)

lower limit = mean - margin of error

= 3 - 1.6 = 1.4

upper limit = mean + margin of error

= 3 + 1.6 = 4.6

so, the confidence interval is

1.4 < u < 4.6