A farmer buys three cows two pigs and for hens from a man w

A farmer buys three cows , two pigs and for hens from a man who has six cows , five pigs and eight hens. Determine the choices that the farmer have.

The number ways we can buy 3 cows from six cows = 6C3.=6*5*4/3*2*1 =20

The number ways we can buy 2pigs from 5 pigs = 5C2 = 5*4/2*1 = 10

The number of ways we can buy 4 hens from 8hens = 8C4 = 8*7*6*5/4*3*2*1 = 70.

Since each of the activity is independent, we multiply the number of each of the ways that could be done = 20 *10*70 ways in all

= 14000 diffeent ways.