In box 1 there are 15 marbles 4 white and 11 black In box 2

In box 1 there are 15 marbles, 4 white and 11 black. In box 2 there are 8 marbles, 5 white and 3 black. If one marble is drawn from box 1 and one from box 2. Find the probability that at least one white marble is drawn.

Solution

There are two boxes

the box1 contain 15 marbles out of that white=4

black=11

The box 2 contains 8 marbles out of that white=5

black=3

Now to drawn one ball is drawn from box 1 and one from box2.

Now to find the p(at least one white marble is drawn)+p(at least no white ball is drawn)=1

p(at least one white marble is drawn)=1-p(at least no white ball is drawn)

=1-[p(no whiteball is drawn from box1)*P(no white ball is drawn from box2)]

= 1-(11c1/15c1*3c1/8c1)

=1-(11/15*3/8)

=1-(0.733*0.375)

=1-0.274875

=0.725125