Write a C program that has an integer array variable Userval
Solution
a)
 #include <stdio.h>
 #include<iostream>
 int main()
 {
     int UserValue[500], *minimum, size, c, location = 1;
 
     cout<<\"Enter the number of elements in array\"<<endl;
     cin>>size;
 
     cout<<\"Enter \"<<size<<\" integers\";
     for ( c = 0 ; c < size ; c++ )
         cin>>UserValue[c];
 
     minimum = UserValue;
     *minimum = *UserValue;
 
     for ( c = 1 ; c < size ; c++ )
     {
         if ( *(UserValue+c) < *minimum )
         {
            *minimum = *(UserValue+c);
            location = c+1;
         }
     }
         cout<<\"Minimum element found at location \"<< location<<\" and it\'s value is \"<< *minimum<<end;
     return 0;
 }
 b)
#include<conio.h>
 #include<iostream>
 void main()
 {
 char str[100];
 char *p,*t;
 cout<<\"Enter any string : \";
 gets(str);
 for(p=str ; *p!=NULL ; p++);
 for(t=str, p-- ; p>=t; )
 {
     if(*p==*t)
     {
         p--;
         t++;
     }
     else
         break;
 }
 if(t>p)
        cout<<\" String is Palindrome\";
 else
        cout<<\" String is not Palindrome\";
 getch();
 }
c)
 #include<conio.h>
 #include<iostream>
 void main()
 {
 int size;
 cin >> size;
 double *num_array[] = new double[size];
 double* a = num_array;
 double total = 0;
 for (int count =0; count< size; count++){
     total = total + *(a + count);
 }
 cout << total/size;
 }


