Two cyclists 120 miles apart start riding toward each other

Two cyclists, 120 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist?

Solution

r=D/t
r=120/4
r=30 mph coming together
divide by three because one is twice as fast as the other
slower=10 mph
faster=20mph