The maximum power a device can dissipate is 05W Determine th

The maximum power a device can dissipate is 0.5W. Determine the maximum current allowed by the device rating when the voltage is 9V. Two electrical devices are connected as shown in figure 2. Find the power transferred and state whether the power is transferred from A to B or from B to A when: V = +11 V and I= -1.1 A V = +80V and I = +20mA V =-120V and I =-12mA V= -1.5V and I = -600 mu A

Solution

Ans)

Problem 3) Given Maximum Power Pmax=0.5 W

   Voltage V=9 V

Maximum Current Imax=Pmax/V =0.5/9=0.055 A

Imax=0.055 A

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Problem 4)

a) V=11 V I=-1.1 A

Power=V*I=11*-1.1=-12.1 W negative so power transferred from B to A

b) V=80 V I=20 m A

Power=V*I=80*20m=1.6 W positive so power transferred from A to B

c) V=-120 V I=-12m A

Power=V*I=-120*-12m=1.44 W positive so power transferred from A to B

d) V=-1.5 V I=-600u A

Power=V*I=-1.5*-600u=0.9 W positive so power transferred from A to B