A particle is moving so that its velocity vt t 64t2 for 2
A particle is moving so that its velocity, v(t) = t - 64/t2 for -2 le t le 6. Find the total distance travelled by the particle.
Solution
v = t - (64/t2 ) for -2< t <6
when velocity equals zero t = 64/t2
t3 = 64
t = 4
upto 4s velocity will b negative then it wil change to positive
so on integration v = t2/2 + 64/t
applying limits -2<t<4 and 4<t<6 separatly
v = 54 + 4.67 = 58.67m
