If the membrane shown in the beakers is permeable only to Na

If the membrane shown in the beakers is permeable only to Na^+, and the beaker on the left represents the initial state, which of the following will occur? Select one: a. Na^+ will diffuse to the left side of the membrane, causing a net positive charge on the right tide of the membrane. b. Na^+ will diffuse to the left side of the membrane, causing a not negative charge on the right side of the membrane. c. Na^+ will be transported to the left side of the membrane, causing a not negative charge on the right side of the membrane d. The movement of Na^+ will be balanced out by the movement of K; therefore, there will be no net charge difference.

Solution

The answer is first option..

The movement of the sodium ions will be from right to left side of the beaker thus causing the positive charge on the right side of the membrane..! As the sodium ions is lost there is decrease in the sodium ions concentration hence the side acquire the positive charge..!! Positive charge indicates loss of ions..!