A passenger car traveling down a rough road bounces up and d
A passenger car traveling down a rough road bounces up and down at 1.5 Hz with a maximum vertical acceleration of 0.23 m/s2 , both typical values.
Solution
f = 1.5 Hz
a_max = 0.23 m/s^2
a_max = ^2Y
0.23 = (2*pi*f)^2*Y
Y = 0.23 / 88.73
Y = 2.5919*10^-3 m
V_max = Y = 2*pi*f*Y
V_max = 2*pi*1.5*2.5919*10^-3
V_max = 0.0244156 m/s
