An electron that has velocity v bar 21 times 106 ms i 23 ti

An electron that has velocity v bar (2.1 times 10^6 m/s) i + (2.3 times 10^6 m/s) J moves through a magnetic field B = (0 03 T) i - (0.15 T) J Find the force on the electron. N Repeat your calculation for a proton having the same velocity. N

Solution

A. F = q*VxB

VxB =

= |i j k|

= |2.1 2.3 0|

= |0.03 -0.15 0|

VxB = -2.1*10^6*0.15 - 0.03*10^6*2.3 = -0.384*10^6 k

F = q*(VxB) = -1.6*10^-19*(-0.384*10^6) = 6.14*10^-14 k

direction is +z

B.

for proton q = +1.6*10^-19

F = -6.14*10^-14 k

direction is -z