Add 24five 33five in base five The numbers are already writ

Add 24_five + 33_five in base five. (The numbers are already written in base five, so there should be no conversions done.) How would you illustrate this with the base five blocks using drawings and showing the intermediate steps?

Solution

8).

24 (base 5) +33(base 5)

if we add directly the answer will be 24+33=57 (but in base \'5\' we only get values from 0 to 5)

so the answer is wrong

we will convert them into decimal and add them then convert tha answer to base \'5\'

24(base 5) = 2*(5^1) +4*(5^0)

=2*5 +4*1

= 10+4

=14 (in decimal)

33(base5) = 3*(5^1) +3*(5^0)

= 3*5 +3*1

=15+3

=18

now add them 14+18 =32

now we convert this into base \'5\' by dividing 32 with 5

5 32

6 2(reminder)

1 1 (reminder)

so 112(in base 5)

so the answer is 112