If x is normally distributed with mean and standard deviatio

If x is normally distributed with mean and standard deviation =4, and given that the probability that x is less than 32 is 0.0228. Find the value of .

Solution

P(X < 32) = 0.0228

P( 31-u/4) = 0.0228

=>

31 - u / 4 = invnorm(0.0228)

=>

31 -u /4 = -1.999

=>

u = 38.996 = 39