If the wind is blowing the wedges of air across the front of

If the wind is blowing the ``wedges\" of air across the front of the 20 cm telescope at 10 km per hour then how long does it take for a wedge to cross the front of the telescope? What does this mean to a tip-tilt system of adaptive optics?

Solution

speed of the wind is

                v = 10 km / h = (10) ( 1000 ) / 3600 s ) = 2.77 m/s

time taken by the wind to cross the front of the telescope

             t = d / v

                = 20 cm/ 2.77 m/s = 0.072 s