Determine the area under the standard normal curve that lies

Determine the area under the standard normal curve that lies between (a) Z = -0.56 and Z = 0.56, (b) Z = -2.82 and Z=0,and(c)Z = -0.38 and Z = 0.24. (a) The area that lies between Z = -0.56 and Z = 0.56 is . (Round to four decimal places as needed.) (b) The area that lies between Z = -2.82 and Z = 0 is . (Round to four decimal places as needed.) (c) The area that lies between Z = -0.38 and Z = 0.24 is . (Round to four decimal places as needed.)

Solution

(a) P(-0.56<Z<0.56) =0.4245 (from standard normal table)

(b) P(-2.82<Z<0) = 0.4976 (from standard normal table)

(c) P(-0.38<Z<0.24) =0.2429 (from standard normal table)