Assume that a simple random sample has been selected from a
Solution
A)
Formulating the null and alternative hypotheses,              
               
 Ho:   u   >=   21.1  
 Ha:    u   <   21.1  
               
 As we can see, this is a    left   tailed test.      
               
               
 Getting the test statistic, as              
               
 X = sample mean =    19.4          
 uo = hypothesized mean =    21.1          
 n = sample size =    25          
 s = standard deviation =    3.85          
               
 Thus, z = (X - uo) * sqrt(n) / s =    -2.207792208          
               
 Thus, the p value is              
               
 p =    0.013629381   [ANSWER]
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b)      
               
 As P < 0.05, we reject Ho.
Thus, it is OPTION B. There is sufficient evidence to support the claim that the mean tar content of filtered 100 mm cigarettes is less than 21.1 mg. [ANSWER, B]
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c)
OPTION D: The results suggest that the filters are effective. [ANSWER, D]

