Assume that a simple random sample has been selected from a
Solution
A)
Formulating the null and alternative hypotheses,
Ho: u >= 21.1
Ha: u < 21.1
As we can see, this is a left tailed test.
Getting the test statistic, as
X = sample mean = 19.4
uo = hypothesized mean = 21.1
n = sample size = 25
s = standard deviation = 3.85
Thus, z = (X - uo) * sqrt(n) / s = -2.207792208
Thus, the p value is
p = 0.013629381 [ANSWER]
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b)
As P < 0.05, we reject Ho.
Thus, it is OPTION B. There is sufficient evidence to support the claim that the mean tar content of filtered 100 mm cigarettes is less than 21.1 mg. [ANSWER, B]
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c)
OPTION D: The results suggest that the filters are effective. [ANSWER, D]
